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Home/ Questions/Q 6636197
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T23:09:20+00:00 2026-05-25T23:09:20+00:00

I am trying to convert my current code to MySQLi extension… But I have

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I am trying to convert my current code to MySQLi extension… But I have a problem with this code..

    $sql = "SELECT COUNT(*) FROM users WHERE username='$username'";
    $result = mysql_query($sql);
    if (mysql_result($result, 0) > 0) {
  $errors[] = 'The username is already taken.';
    }

What is the mysqli function of “mysql_result” ? I can’t get it work.

My current MySqLi code is just the connection and

    $sql = "SELECT COUNT(*) FROM users WHERE username='$username'";
    $result = $mysqli->query($sql);
    if (mysql_result($result, 0) > 0) {
  $errors[] = 'The username is already taken.';
    }

But I need to change the mysql_result, but can’t find the opposite function in MySQLi..

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T23:09:21+00:00Added an answer on May 25, 2026 at 11:09 pm

    I usually use the object-y interface to MySQLi:

    <?php
    $db = new mysqli($hostname, $username, $password, $database);
    $result = $db->query('SQL HERE');
    
    // OOP style
    $row = $result->fetch_assoc();
    $row = $result->fetch_array();
    
    while($row = $result->fetch_row())
    {
        // do something with $row
    }
    
    // procedural style, if you prefer
    $row = mysqli_fetch_assoc($result);
    $row = mysqli_fetch_array($result);
    
    while($row = mysqli_fetch_row($result))
    {
        // do something with $row
    }
    ?>
    

    Full list of result methods is here: http://www.php.net/manual/en/class.mysqli-result.php

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