I am trying to convert some Verilog code that produces a slower clock from a faster clock for a UART module. The original verilog code is based on the module over at fpga4fun.com, and this is my attempt to translate it for my VHDL-based design.
entity baud_generator is
generic(
f_clk : integer := 50000000; -- default: 50 MHz
baud : integer := 115200; -- default: 115,200 baud
accum_width : integer := 16;
accum_inc : integer := (baud sll accum_width) / f_clk
);
port(
clock : in std_logic;
reset_n : in std_logic;
enable : in std_logic;
baud_clock : out std_logic
);
end entity baud_generator;
However, my compiler, Aldec-HDL, doesn’t like the following line:
accum_inc : natural := (baud sll accum_width) / f_clk
Here is the exact error message:
# Error: COMP96_0300: baud_generator.vhd : (20, 52): Cannot reference "f_clk" until the interface list is complete.
# Error: COMP96_0300: baud_generator.vhd : (20, 28): Cannot reference "baud" until the interface list is complete.
# Error: COMP96_0071: baud_generator.vhd : (20, 28): Operator "sll" is not defined for such operands.
# Error: COMP96_0104: baud_generator.vhd : (20, 27): Undefined type of expression.
# Error: COMP96_0077: baud_generator.vhd : (20, 27): Assignment target incompatible with right side. Expected type 'INTEGER'.
In verilog, I have something like this:
module baud_generator(
input clock,
input reset_n,
input enable,
output baud_clock
);
parameter f_clock = 50000000;
parameter baud = 115200;
parameter accum_width = 16;
parameter accum_inc = (baud << accum_width) / f_clock;
//...
endmodule
What is it that I need to modify in that line to make the compiler happy? Is it possible to use generics chained together like that?
This basically says you cannot do computations with the generic values to caluclate (default values for) other generics.
Just use
accum_incas a constant, not as a generic.Also, the SLL (shift logic left) operator is meant for bit patterns (
unsignedandsigneddatatypes in theieee.numeric_stdandieee.numeric_bitpackages), not for integers. You can do the same by multiplying by a power of two.