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Home/ Questions/Q 8594277
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T00:09:38+00:00 2026-06-12T00:09:38+00:00

I am trying to convert this python code that sorts my items list into

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I am trying to convert this python code that sorts my items list into java code. How can i do this kind of sorting in java?

python code:

import re
items = ['10H', '10S', '2H', '3S', '4S', '6C', '7D', '8C', '8D', '8H', '11D', '11H', '12H']
sortedItems = sorted(items, key=lambda x:int(re.findall(r'(\d+)[A-Z]*$',x)[0]))

#print sortedItems will result to the following sorted data which is what i wanted
#['2H', '3S', '4S', '6C', '7D', '8C', '8D', '8H', '10H', '10S', '11D', '11H', '12H']

So far what i have in java is the following:

//code something like this
ArrayList<String> items = new ArrayList<String>(Arrays.asList("10H", "10S", "2H", "3S", "4S", "6C", "`7D", "8C", "8D", "8H", "11D", "11H", "12H"));
Collections.sort(items)

Thanks

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  1. Editorial Team
    Editorial Team
    2026-06-12T00:09:40+00:00Added an answer on June 12, 2026 at 12:09 am

    You’ll need to use a custom Comparator in place of the lambda expression declared in your python script.

    Collections.sort(items,  new Comparator<String>() {
        private Pattern p = Pattern.compile("(\d+)[A-Z]*)");
        public int compare(String o1, String o2) {
            Matcher m1 = p.matcher(o1);
            Matcher m2 = p.matcher(o2);
    
            return Integer.valueOf(m1.group(0)).compareTo(Integer.valueOf(m2.group(0)));
        }
    });
    

    Please note that this Comparator doesn’t compare the letter component, simply because the lambda expression doesn’t either.

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