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Home/ Questions/Q 9051609
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T12:56:48+00:00 2026-06-16T12:56:48+00:00

I am trying to create a bitmap object from raw bytes, my PixelFormat is

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I am trying to create a bitmap object from raw bytes, my PixelFormat is RGB with 8 bits per sample, which is 3 bytes per pixel. now for this my stide will be 3 times the width.

But Bitmap class is always looking for multiplier of 4 for stride value. Please help me how to resolve this issues. if i give multiplier of 4 image is not coming properly.

Bitmap im = new Bitmap(MyOBJ.PixelData.Columns, MyOBJ.PixelData.Rows, (MyOBJ.PixelData.Columns*3),
System.Drawing.Imaging.PixelFormat.Format24bppRgb, Marshal.UnsafeAddrOfPinnedArrayElement(images[imageIndex], 0));
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T12:56:50+00:00Added an answer on June 16, 2026 at 12:56 pm

    I’ve written a short sample which will pad every line of your array to adapt it to the required format. It will create a 2×2 check board bitmap.

    byte[] bytes =
        {
            255, 255, 255,
            0, 0, 0,
            0, 0, 0,
            255, 255, 255,
        };
    var columns = 2;
    var rows = 2;
    var stride = columns*4;
    var newbytes = PadLines(bytes, rows, columns);
    var im = new Bitmap(columns, rows, stride,
                        PixelFormat.Format24bppRgb, 
                        Marshal.UnsafeAddrOfPinnedArrayElement(newbytes, 0));
    

    The PadLines method is written below. I tried to optimize it by using Buffer.BlockCopy in case your bitmaps are large.

    static byte[] PadLines(byte[] bytes, int rows, int columns)
    {
        //The old and new offsets could be passed through parameters,
        //but I hardcoded them here as a sample.
        var currentStride = columns*3;
        var newStride = columns*4;
        var newBytes = new byte[newStride*rows];
        for (var i = 0; i < rows; i++)
            Buffer.BlockCopy(bytes, currentStride*i, newBytes, newStride * i, currentStride);
        return newBytes;
    }
    
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