Question

I am trying to create a char array dynamically. However, do not matter which number I put as the desired value of the size array it just keep using 4 has the size. If I place 3,2 or even 8, 10 it does not change…

Part where I initialize it…

char *x;

x = (char *)calloc(10, sizeof(char));

if(x == NULL )
{
    return;
}

cout <<"Size_Vector = "<<sizeof(x)<<endl; //Keep making the size of the array 4..no matter what

Answer 1

sizeof(x) returns the size of the pointer not the allocated memory or the size of array.

It always returns 4 size of an pointer on your envrionment is 4and it will be the same for all.

You will have to keep track of how much memory you allocated yourself & also ensure that you do not write beyond the bounds of that allocated memory.