Question

I am trying to create a PHP script where text is displayed if the MySQL row id=1 has an entry of 1 in the value field and no text is shown if it has a different value. The script I wrote so far doesn’t seem to work:

<?php

    // connect to the database
    include('connect-db.php');

?>
<?php  $result = mysql_query("SELECT * FROM Cups WHERE id='1'"); if           
($row_queryname['value'] == '1') {?> 
Display text here.
<?php }?>

I am quite new at this so any help would be greatly appreciated!
Thanks.

Answer 1

You need to use one of the “fetch” functions to actually get a row after you make a query. Since you haven’t specified any field names, I’m going to use mysql_fetch_assoc():

<?php
    // connect to the database
    include('connect-db.php');

    $result = mysql_query("SELECT * FROM Cups WHERE id='1'");
    $ar = mysql_fetch_assoc($result);

    if ($ar['fieldname'] == '1')  // Whatever your field name is
    {
?>
Display text here.
<?php
    }
?>

mysql_fetch_assoc() gets an associative array that represents a result row, where the array keys are the field names.

Note: This example does not include any error checking.