I am trying to create a program that will take user inputs(marks) and output the average of these marks to a letter grade.
I believe I have succeded in getting the program to calculate the average succesfully, however it will not output the right letter grade?
Any suggestions?
EDIT: Perhaps it is something in the calculations, because my output always gives the percentage as an “F” grade….
// Used iomanip to display averages for possible three digit or greater answers.
#include <iostream>
#include <iomanip>
using namespace std;
// Set up my program using only main()
int main()
{
//Created the variable 'mark' so the user input can be stored and tested in the do-while condition.
//Variable 'sum' and 'average' to calculate mark and then be tested against letter grades.
//'counter' used to keep track of number of terms being averaged.
double mark=0, sum=0, average=0;
int counter=-1;
// Do-while statement to test the loop. Gets input from user, and tests whether it is a a valid letter grade.
// Marks below 0 or above 100 will test true and loop back re-promting the user for another mark.
// If tested condition is false, then if statements then test the mark and output the letter grade.
cout << "Please enter marks to calculate average, and enter -1 to stop and find letter equivalence. " << endl;
do
{
if ( mark < 0 || mark > 100 )
{
cout << "Entered mark is invalid. Please try again, or enter -1 to stop and find letter equivalence. " << endl;
break;
}
sum = sum + mark;
counter++;
cin >> mark;
}
while ( mark != -1 );
average = sum / counter ;
//What happens when above statement is false...
if (mark >= 90)
{
cout << "The average of "<<setprecision(2)<<average<<"% is equivalent to a letter grade of A+ ";
}
else if (mark >=80)
{
cout << "The average of "<<setprecision(2)<<average<<"% is equivalent to a letter grade of A ";
}
else if (mark >=70)
{
cout << "The average of "<<setprecision(2)<<average<<"% is equivalent to a letter grade of B ";
}
else if (mark >=60)
{
cout << "The average of "<<setprecision(2)<<average<<"% is equivalent to a letter grade of C ";
}
else if (mark >=50)
{
cout << "The average of "<<setprecision(2)<<average<<"% is equivalent to a letter grade of D ";
}
else
{
cout << "The average of "<<setprecision(2)<<average<<"% is equivalent to a letter grade of F ";
}
return 0;
}
Couple of things to consider:
Your grades assignment should consider the
averageand notmarks. If you use marks, then the last entered value which is-1to exit your do while loop will be used to grade which will always result in F grade.Add
endlto all yourcoutstatements after thedo-whileloop. The output stream may have been buffered and this can cause the cout statements to not appear on your monitor.endlwill flush the output stream.For eg.
cout << "The average of "<<setprecision(2)<<average<<"% is equivalent to a letter grade of A+ " << endl;