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Home/ Questions/Q 925297
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T19:29:51+00:00 2026-05-15T19:29:51+00:00

I am trying to create a ripple effect with Jquery. By having an element

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I am trying to create a ripple effect with Jquery. By having an element “bounce” one right after the other. I have it working but not sure as to why it only works this way. First off here is the code.

//First Part (I Don't know why I need it?)
$(elements).queue(function(){
   $(this).fadeTo("fast",1);
   $(this).dequeue();});

//The Actuall Ripple Effect             
for (var i = 0; i < elements.length; i++)                       
    $(elements[i]).effect("bounce",{times:1}).delay(i * 50);
                }

If I were to remove the first part all the elements would bounce at the same time. So My question is why does this happen and is their a way around it?

I am using Jquery 1.4.2
and the “elements” are images inside an inline un-ordered list

//edit I forgot to state that the bounce effect comes from Jquery UI.

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  1. Editorial Team
    Editorial Team
    2026-05-15T19:29:52+00:00Added an answer on May 15, 2026 at 7:29 pm

    You just have .delay() on the wrong side of the effect.

    Try it out: http://jsfiddle.net/MF3A8/ (click the Run button at the top to replay it)

    elements = $('div');
    
    for (var i = 0; i < elements.length; i++) {                   
        elements.eq(i).delay(50 * i).effect("bounce",{times:1});
    }​
    

    And you can use .eq() to reference the proper element in the jQuery object.

    • http://api.jquery.com/eq/
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