Question

I am trying to create a roll-in / roll-out slideshow in jQuery/JavaScript.
My problem is, that it needs to be repeated. And right now when it’s starting over, the pictures doesnt come from the right side anymore 🙁

The reason for which I have created the slideLeft function, is that afterwards I need to create 2 functions, where the user can interrupt the slideshow manually pressing a left or right button.

This is what I’ve got:

<script class="jsbin" src="http://code.jquery.com/jquery-1.7.2.min.js"></script>

<div style='background: #c4c4c4; border: 1px solid #7b7b7b; height: 220px; overflow: hidden; padding: 5px; position: absolute; width: 590px;'>
  <div id='slider-image-1' style='left: 5px; background: red; height: 216px; padding: 2px; position: absolute; top: 5px; width: 586px;'></div>
  <div id='slider-image-2' style='left: 600px; background: yellow; height: 216px; padding: 2px; position: absolute; top: 5px; width: 586px;'></div>
  <div id='slider-image-3' style='left: 600px; background: green; height: 216px; padding: 2px; position: absolute; top: 5px; width: 586px;'></div>
  <div id='slider-image-4' style='left: 600px; background: blue; height: 216px; padding: 2px; position: absolute; top: 5px; width: 586px;'></div>
</div>

<script type='text/javascript'>
  $(document).ready(function() {
    var amount = 0;
    var nextamount = 1;
    setInterval(function() {
      amount++;
      nextamount++;
      if (nextamount === 5) nextamount = 1;
      if (amount === 5) amount = 1;
        slideLeft(amount, nextamount);
      }, 2000);
    });

  function slideLeft(i, j) {
    var $theItem = $('#slider-image-' + i);
    $theItem.animate({
      left: parseInt($theItem.css('left'), 10) == 5 ? -$theItem.outerWidth() : 5
    }, 500);

    var $theItem = $('#slider-image-' + j);
    $theItem.animate({
      left: parseInt($theItem.css('left'), 10) == 5 ? $theItem.outerWidth() + 10 : 5
    }, 500);

  };
</script>

Answer 1

You need to prepare element, which is going to roll in, to be on the right.

function slideLeft(i, j) {
  var $theItem = $('#slider-image-' + i);
  $theItem.animate({
    left: parseInt($theItem.css('left'), 10) == 5 ? -$theItem.outerWidth() : 5
  }, 500);

  var $theItem = $('#slider-image-' + j);
  $theItem.css('left', '600px'); // moves in item to the right before animation
  $theItem.animate({
    left: parseInt($theItem.css('left'), 10) == 5 ? $theItem.outerWidth() + 10 : 5
  }, 500);

};

I think you’ve tried it with your parseInt, but it doesn’t work, so you can get rid of it.

function slideLeft(i, j) {
  var $outItem = $('#slider-image-' + i);
  $outItem.animate({ left: -$outItem.outerWidth() }, 500);

  var $inItem = $('#slider-image-' + j);
  $inItem.css('left', '600px');
  $inItem.animate({ left: 5 }, 500);
}