Question

I am trying to create a script that will run wget to a few sites and check if we receive a 200 OK from the site.

My problem is that the result of wget application is shown in the stdout. Is there a way I can hide this.

My current script is:

RESULT=`wget -O wget.tmp http://mysite.com 2>&1`

Later I will use regex to look for the 200 OK we receive from the errout that wget produces.
When I run the script, it works fine, but I get the result of the wget added between my echos.

Any way around this?

Answer 1

You can use:

RESULT=`wget --spider http://mysite.com 2>&1`

And this does the trick too:

RESULT=`wget -O wget.tmp http://mysite.com >/dev/null 2>&1`

Played around a little and came up with that one:

RESULT=`curl -fSw "%{http_code}" http://example.com/ -o a.tmp 2>/dev/null`

This outputs nothing but “200” – Nothing else.