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Home/ Questions/Q 4580418
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T20:46:51+00:00 2026-05-21T20:46:51+00:00

I am trying to create a stupid loading div. I just want it to

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I am trying to create a stupid loading div. I just want it to show everytime a button is clicked. I have a gif named ajaz-loader.gif located in img/

I have this and it doesn’t work… I just found it on the internet. Any ideas?

    <script>
    $('#loadingDiv').ajaxStart(function() {
      $(this).show();
    }).ajaxComplete(function() {
    $(this).hide();
    });
     </script>
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  1. Editorial Team
    Editorial Team
    2026-05-21T20:46:52+00:00Added an answer on May 21, 2026 at 8:46 pm

    Make sure to wrap your code inside a

    $(function() {
      // YOUR CODE HERE
    });
    

    Then if it still doesn’t work, double check if your #loadingDiv

    That looks like this 🙂

    Display loading while webservice is running

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