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Home/ Questions/Q 7692953
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Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T20:58:19+00:00 2026-05-31T20:58:19+00:00

I am trying to create a table within PHP code in order to open

  • 0

I am trying to create a table within PHP code in order to open in a browser to create the table. I need a varying array within the table and have the correct code to create it in Oracle:

CREATE TYPE ReportEntries_Type AS OBJECT
(Subject VARCHAR (500));
/

CREATE OR REPLACE TYPE ReportEntries_VA AS
VARRAY (12) OF ReportEntries_Type;
/

CREATE TABLE ReportDetails
(ReportID INTEGER NOT NULL UNIQUE,
StudentID INTEGER NOT NULL UNIQUE,
ReportEntries ReportEntries_VA,
DateLastModified DATE NOT NULL,
CONSTRAINT ReportDetails_PK PRIMARY KEY (ReportID, StudentID),
CONSTRAINT RDStudentIDSD FOREIGN KEY (StudentID)
REFERENCES StudentDetails (StudentID));

However, when placed within PHP code and added to a MySQL database, an error message appears. The code I’m using is as follows:

<?php
require "connect_to_mysql.php";

$sqlCommand = "CREATE TYPE ReportEntries_Type AS OBJECT

...cont. code from above...

REFERENCES StudentDetails (StudentID))";

if (mysql_query ($sqlCommand)) {
echo "The ReportDetails table has been created successfully!";
} else {
echo "There has been an error";
}
?>

Is it even possible? Many thanks in advance 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T20:58:20+00:00Added an answer on May 31, 2026 at 8:58 pm

    No, it’s not really possible, sorry 🙁

    In MySQL, we usually use VARCHAR or TEXT fields with coma separated values to do that. I know, it’s annoying 🙂

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