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Home/ Questions/Q 6812779
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Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T20:29:27+00:00 2026-05-26T20:29:27+00:00

I am trying to create a thread in an object, however I get an

  • 0

I am trying to create a thread in an object, however I get an error saying '&' : illegal operation on bound member function expression. Reading up I saw I have to make the member function static, but when I do that I get an error saying left of '.dac_ping' must have class/struct/union

this is what I am trying:

class Dac 
    {
    private:
        network_com com;
        HANDLE  ping_thread;
        DWORD   dping_thread;

        static DWORD WINAPI ping_loop(void* param)
            {
            while ( com.dac_ping() == 0)
                Sleep(900);

            return 1; //since this is an infinite loop, if the loop breaks, it has failed
            }


    public:
        Dac()
            {
            }

        ~Dac()
            {
            }

        void find_dac()
            {
            com.find_dac();
            com.print_dac_info();
            }


        void connect_and_keep_alive()
            {
            if (com.dac_connect() == 0)
                ping_thread = CreateThread (NULL , 0, ping_loop, NULL, 0, &dping_thread);
            }

    };
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  1. Editorial Team
    Editorial Team
    2026-05-26T20:29:28+00:00Added an answer on May 26, 2026 at 8:29 pm

    static functions aren’t bound to a particular instance; there is no this pointer, and you have no “member variables.” You can pass the this pointer as an argument to your function, and then cast it into a Dac* and access member variables from it.

    So you could do

    ping_thread = CreateThread (NULL , 0, ping_loop, (LPVOID)this, 0, &dping_thread);
    

    And change your ping_loop to this:

    static DWORD WINAPI ping_loop(void* param)
    {
        Dac* dac = (Dac*)param;
        while ( dac->com.dac_ping() == 0)
            Sleep(900);
    
        return 1; //since this is an infinite loop, if the loop breaks, it has failed
    }
    
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