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Home/ Questions/Q 8046495
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T05:48:14+00:00 2026-06-05T05:48:14+00:00

I am trying to create a thread using pthread. So far I have this:

  • 0

I am trying to create a thread using pthread. So far I have this:

sample.h:

void* ReceiveLoop(void*);
pthread_t mythread;

sample.cpp:

void* ReceiveLoop(void*) {
  cout<<"whatever";
}

void sample::read() {
  pthread_create(&mythread, NULL, ReceiveLoop, NULL);
}

Which I think is ok having read some posts about this. I have also tried with

pthread_create(&mythread, NULL, &ReceiveLoop, NULL);

But I get this:

.cpp:532: error: no matches converting function 'ReceiveLoop' to type 'void* (*)(void*)'
.cpp:234: error:                 void* sample::ReceiveLoop(void*)

Anyone can help me? Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T05:48:16+00:00Added an answer on June 5, 2026 at 5:48 am

    I recall a few idiosyncrasies between older versions of gcc/g++ with regards to errors like this. You didn’t indicate the compiler you were using.

    Go ahead and give the void* parameter passed to ReceiveLoop a name:

     void ReceiveLoop(void* threadarg);
    
     void* ReceiveLoop(void* threadarg){ cout<<"whatever"; }
    

    For some reason, I seem to recall that’s the only way I could get a particular piece of code to compile on some random compiler even though the parameter passed in wasn’t actually used.

    Also, if ReceiveLoop is a member function of a class, it needs to be declared static.

    class sample
    {
     public:
    
        void ReceiveLoopImpl()
        {
            cout<<"whatever";
        }
    
        static void* ReceiveLoop(void* threadargs)
        {
            return ((sample*)threadargs)->RecieveLoopImpl();
        }
    
        void read()
        {
             pthread_create(&mythread, NULL, sample::ReceiveLoop, this);
        }
    
    };
    
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