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Home/ Questions/Q 6950639
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T14:07:02+00:00 2026-05-27T14:07:02+00:00

I am trying to create li elements based on the number of values in

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I am trying to create li elements based on the number of values in array.
Basically, for every key in an array an li element needs to be created.

<ul class="alpharow">
</ul>
    $(".alpharow").each(function() {

    var alpha = new Array();
        alpha['this'] = ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
        alpha['that'] = ['l', 'm', 'n', 'o', 'p', 'q', 'r'];
     var n = alpha.length;

        for (i = 0; i < n; i++) {
            //$("li:eq(" + i + ")");

           var li_tag = '<li class="alpha_li"></li>';
        }

        $(".alpharow").append(li_tag);

        //$("span").text("There are " + n + " kys.");

    });

So, a, b, c etc…would all have their own <li>

Thanks for the help, let me know if something is not clear.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T14:07:03+00:00Added an answer on May 27, 2026 at 2:07 pm

    You have array of arrays. If you need to create LIs for all of them use such sample:

    $(".alpharow").each(function() {
    
        var alpha = new Array();
        alpha['this'] = ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
        alpha['that'] = ['l', 'm', 'n', 'o', 'p', 'q', 'r'];
    
        // go thru the main array
        for (var key in alpha) {
            // go thru the inner arrays
            var arr = alpha[key];
            for (i = 0, n = arr.length; i < n; i++) {
                //apped LI's
                $(".alpharow").append($('<li></li>', { class: 'alpha_li', text: arr[i] }));
            }
        }       
    });
    

    Code: http://jsfiddle.net/m8vwz/1/

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