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Home/ Questions/Q 8527745
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T08:38:33+00:00 2026-06-11T08:38:33+00:00

I am trying to create linear correlation graph between to variables using ggplot2 :

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I am trying to create linear correlation graph between to variables using ggplot2:

dput(sum)
structure(list(Date = structure(c(15218, 15248, 15279, 15309, 
15340, 15371, 15400, 15431, 15461, 15492, 15522, 15553), class = "Date"), 
    Teams = c(87, 142, 173, 85, 76, 76, 93, 49, 169, 139, 60, 
    120), Scores = c("67101651", "62214988", "63183320", "66750198", 
    "61483322", "67546775", "75290893", "60713372", "77879142", 
    "70290302", "83201853", "83837301")), .Names = c("Date", 
"Teams", "Scores"), row.names = c(NA, 12L), class = "data.frame")

this is my command:

ggplot(sum, aes(x = Scores, y = Teams, group=1)) + 
    geom_smooth(method = "lm", se=TRUE, size=2, formula = lm(Teams ~ Scores))

I get this error:

Error in eval(expr, envir, enclos) : object 'Teams' not found

any ideas?

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  1. Editorial Team
    Editorial Team
    2026-06-11T08:38:34+00:00Added an answer on June 11, 2026 at 8:38 am

    If you want to specify the formula for, e.g., linear model, use y ~ poly(x, 1). You don’t need to change the formula parameter as long as you want a simple linear regression (it’s the default for method = "lm"):

    ggplot(sum, aes(x = Scores, y = Teams, group = 1)) +
      geom_smooth(method = "lm", formula = y ~ poly(x, 1), se = TRUE, size = 2)
    

    I also would recommend using Scores as numeric values (as.numeric(Scores)) if you don’t want this variable to be categorial. This would change the regression line.

    Score as categorial variable:

    categorial

    Score as numeric variable:

    numeric

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