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Home/ Questions/Q 8918597
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T05:47:48+00:00 2026-06-15T05:47:48+00:00

I am trying to create slugs. My string is like this: $string=’möbel#*-jérôme-mp3-how?’; Step: 1

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I am trying to create slugs. My string is like this: $string='möbel#*-jérôme-mp3-how?';

Step: 1

First, I want to remove special characters, non-alphanumeric and non-latin characters from this string.

Like this: $string='möbel-jérôme-mp3-how';

Previously, I used to have only english characters in the string.

So, I used to do like this: $string = preg_replace("([^a-z0-9])", "-", $string);

However, since I also want to retain foreign characters, this is not working.

Step: 2

Then, I want to remove the all the words that have one or more numbers in them.

In this example string, I want to remove the word mp3 as it contains one or more numbers.

So, the final string looks like this: $string='möbel-jérôme-how';

I used to do like this:

$words = explode('-',$string);
$result = array();

foreach($words as $word) 
{
if( ($word ==preg_replace("([^a-z])", "-", $word)) && strlen($word)>2)  
$result[]=$word;
}
$string = implode(' ',$result);

This does not work now as it contains foreign characters.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T05:47:50+00:00Added an answer on June 15, 2026 at 5:47 am

    In PHP, you have access to Unicode properties:

    $result = preg_replace('/[^\p{L}\p{N}-]+/u', '', $subject);
    

    will do step 1 for you. (\p{L} matches any Unicode letter, \p{N} matches any Unicode digit).

    Removing words with digits is just as easy:

    $result2 = preg_replace('/\b\w*\d\w*\b-?/', '', $result);
    

    (\b matches the start and end of a word).

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