Question

I am trying to create table to my database from php. I kinda trying to make a social networking site, anyway, I wrote the code and is working but new table won’t create in database, I don’t know what seems to be wrong with the code. Help will be much appreciated thanks!

<?php

    $host = "host";   
    $user = "user";
    $pswd = "password";
    $dbnm = "db";

    $conn = @mysqli_connect($host, $user, $pswd, $dbnm);
    if (!$conn)
        die ("<p>Couldn't connect to the server!<p>");

    $selectData = @mysqli_select_db ($conn, $dbnm);
    if(!$selectData)
    {
        die ("Database Not Selected");
    }

        $sql = "CREATE TABLE IF NOT EXIST 'friends' 
            (
            'friend_id' INT NOT NULL auto_increment, 
            'friend_email' VAR CHAR(20) NOT NULL,
            'password' VAR CHAR(20) NOT NULL,
            'profile_name' VAR CHAR(30) NOT NULL,
            'date_started' DATE NOT NULL,
            'num_of_friends' INT unsigned,
            PRIMARY KEY ('friend_id')
            )";

    $query_result = @mysqli_query($conn, $sql);


    mysqli_close($conn);

?>

Answer 1

You need to check for errors when running scripts also, so either turn off suppression (remove the @ symbol) or else check for an error after running.

There were in fact multiple errors:

1. You had EXIST rather than EXISTS
2. You used single quotes ( ‘ ) rather than the ` mark

3. You had VAR CHAR as two words, rather than the correct VARCHAR (one word)

     CREATE TABLE IF NOT EXISTS  `friends`  
         (  
         `friend_id` INT NOT NULL auto_increment,   
         `friend_email` VARCHAR(20) NOT NULL,  
         `password` VARCHAR(20) NOT NULL,  
         `profile_name` VARCHAR(30) NOT NULL,  
         `date_started` DATE NOT NULL,  
         `num_of_friends` INT unsigned,  
         PRIMARY KEY (`friend_id`)  
         )