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Home/ Questions/Q 6062819
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T09:05:42+00:00 2026-05-23T09:05:42+00:00

I am trying to declare 2 variables to the same value ( false ).

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I am trying to declare 2 variables to the same value ( false ).

I tend to do this all over the place ( like, in almost every object I prototype )

var $a= {border:false
,frame:false};

or alternately

border=false;frame=false;

Is there better way I can declare the value of both simultaneously? ( eg a code golf solution )

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  1. Editorial Team
    Editorial Team
    2026-05-23T09:05:43+00:00Added an answer on May 23, 2026 at 9:05 am

    You can, if both variables are declared when you set the value. This is kind of quirky, but it works:

    var frame, 
        border = frame = false;
    

    (this would be the shortest you can get I think)

    Is it better? I don’t think so, and you don’t really save much. More readable is

    var frame = false, 
        border = false;
    

    Actually there some more combinations you could do, but you cannot do it without repeating either a variable name or the value. E.g. you could also do:

    var frame = false, 
        border = frame;
    

    Of course this only works for primitive values (i.e. booleans, (literal) numbers, (literal) strings). If you deal with objects (which includes arrays), then both variables would reference the same object. In this case you really have to initialize them separately:

    var frame = {}, 
        border = {};
    
    // DON'T DO THIS:
    var frame, 
        border = frame = {};
    

    Update, because I feel the need to explain why var border = frame = false; does not work:

    var is not transitive here and this expression is actually evaluated from right to left. First, false is assigned to frame, which will be looked up in the scope chain and in the worst case will become global. Then the value of frame is assigned to the local variable border.

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