Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6323999
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 24, 20262026-05-24T16:37:32+00:00 2026-05-24T16:37:32+00:00

I am trying to decode the magnetic heading that is contained in a 10bit

  • 0

image

I am trying to decode the magnetic heading that is contained in a 10bit field. I am not sure how the above instructions are interpreted. What i did is just took the 10 bits and convert them to decimal like this

int magneticheading = Convert.ToInt32(olotoMEbinary.Substring(14, 10), 2);

But then i checked that 259degrees only need 9bits to be expressed in binary (100000011). I am confused about what does a most significant bit of 180 degrees mean and a lsb of 360/1 024 .

For example if i receive the following 10bits 0100001010 how are they converted to degrees according to the above instructions?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-24T16:37:34+00:00Added an answer on May 24, 2026 at 4:37 pm

    Using floating-point math, multiply by 360 and divide by 1024.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm trying to put together something to decode a Json string and not having
I'm trying to decode a JSON feed containing some Cyrillic characters. Not all of
I'm trying to decode a JSON feed containing some Cyrillic characters. Not all of
Hey guys, just trying to decode my signed request.. I've done a bit of
We are trying to decode some uuencoded PDF files that are embedded in a
Hey, I'm trying to decode a multilevel Caesar cipher. By that I mean a
I'm trying to decode a jpeg that is in CMYK color format. BitmapFactory returns
I'm a beginner to Python trying to decode this javascript sequence. I'm not only
some time i trying to decode my own general file that contain the all
Trying to decode an invalid encoded utf-8 html page gives different results in python,

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.