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Home/ Questions/Q 4605956
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T00:30:02+00:00 2026-05-22T00:30:02+00:00

i am trying to display a jquery popup after a fileupload action? not sure

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i am trying to display a jquery popup after a fileupload action? not sure how to code this?

 <%= Html.BeginForm("Upload","Home",FormMethod.Post,new { enctype = "multipart/form-data" }) %>
<%{ %>


<input type="file" id="upload" name="upload" />

<button id="btnUpload">
    upload</button>



<%} %>

 <script type="text/javascript">

    function SayFinished() {
        alert('Finished');
    }
 </script>

[HttpPost]
    public ActionResult Upload()
    {
        HttpPostedFileBase selectedFile = Request.Files["upload"];

        if (selectedFile.ContentLength > 0 )
        {
            //do some processing call jquery script to open popup: SayFinished()
        }

        return View("Index");
    }
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  1. Editorial Team
    Editorial Team
    2026-05-22T00:30:02+00:00Added an answer on May 22, 2026 at 12:30 am

    The simplest way to do this is to return a view from your controller after the post that has an onload script.

    On the new view, put the following javascript:

    In the controller set the following after file uploaded

    ViewData["FileUploaded"] = "true";
    

    Then in the view set

    <% if (!String.IsnullOrEmpty(ViewData["FileUploaded"]) && ViewData["FileUploaded"] == "true") { %>
         <script type="text/javascript">
            $(document).ready(function() {
                SayFinished();
            });
    
            function SayFinished() {
                alert('Finished');
            }
         </script>
    <%} %>
    
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