Question

I am trying to divide an integer by a double value but i believe its losing precision..

#include <cmath>
#include <cstdio>
int main()
{
    double t=5465/54.0;
    double t1=(double)5465/(double)(t);
    double t3 = 5465.0/101.203;
    printf("%lf %lf %lf\n",t,t1,t3);
    return 0;
}

For the above code value of t3 = 54.0003 is as expected but for t1 it becomes 54 instead of getting same value as t3.
I can’t get what mistake am i doing

Answer 1

The value of 5465/54.0 is 101.203703704 (to 9 decimal places). In your code you are using this

 double t3 = 5465.0/101.203;

truncating the result of

 double t=5465/54.0;

to 101.203 for some unknown reason. Therefore you are calculating 2 different values as a result of the truncation. Essentially you are expecting these 2 calculations to be the same but

 5465.0/101.203 != 5465/101.203703704