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Home/ Questions/Q 6934043
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:54:35+00:00 2026-05-27T11:54:35+00:00

I am trying to do a select all script with custom checkboxs and what

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I am trying to do a select all script with custom checkboxs and what is happening is that the result number will update however it shows the count up because each checkbox submits the form to get the accurate result number. however when doing the select all which will initiate the click event it shows the number progressing and i want it to only show once the .each event is done. with the current code it will not run the second function to show the div again here is my code for it any help would be great:

$('.select_all').live('click',function(){
    $('#psf_search_results_number').hide();
    $('.psf_grp_content input[name="type[]"]').each(function(){
        $(this).click();
    });
    return false;
},function(){
    $('#psf_search_results_number').show();
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:54:36+00:00Added an answer on May 27, 2026 at 11:54 am

    I think you should do (but i’m mind reading beacuse it’s not really clear to me what your problem is):

    $('.select_all').live('click',function(){
        $('#psf_search_results_number').hide();
        $('.psf_grp_content input[name="type[]"]').each(function(){
            $(this).click();
        });
        $('#psf_search_results_number').show();
        return false;
    });
    

    you can’t pass two function to live() , if you want to execute show() after the each() just put it after it

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