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Home/ Questions/Q 8204699
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T07:58:29+00:00 2026-06-07T07:58:29+00:00

I am trying to do some simple text processing in Haskell, and I am

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I am trying to do some simple text processing in Haskell, and I am wondering what might me the best way to go about this in an FP language. I looked at the parsec module, but this seems much more sophisticated than I am looking for as a new Haskeller. What would be the best way to strip all the punctuation from a corpus of text? My naive approach was to make a function like this:

removePunc str = [c | c <- str, c /= '.',
                                 c /= '?',
                                 c /= '.',
                                 c /= '!',
                                 c /= '-',
                                 c /= ';',
                                 c /= '\'',
                                 c /= '\"',]
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  1. Editorial Team
    Editorial Team
    2026-06-07T07:58:30+00:00Added an answer on June 7, 2026 at 7:58 am

    You can simply write your code:

    removePunc = filter (`notElem` ".?!-;\'\"")
    

    or

    removePunc = filter (flip notElem ".?!-;\'\"")
    
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