Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7721249
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 1, 20262026-06-01T03:52:34+00:00 2026-06-01T03:52:34+00:00

I am trying to do this List<String> stringList = new ArrayList<String>(); stringList.add(one); stringList.add(two); stringList.add(three);

  • 0

I am trying to do this

List<String> stringList = new ArrayList<String>();
stringList.add("one");
stringList.add("two");
stringList.add("three");

(String[]) stringList.toArray();

why does this gives me class cast exception ?

Caused by: java.lang.ClassCastException: [Ljava.lang.Object;
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-01T03:52:36+00:00Added an answer on June 1, 2026 at 3:52 am

    Better try this other method:

    String[] stringArray = stringList.toArray(new String[stringList.size()]);
    

    In that way the array returned is of the exact type that you need, no cast needed. The method you’re invoking returns an Object[], not a String[] and the cast you’re trying to perform is invalid.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am trying to do this: List<Parent> test = new List<Child>(); The complete code
I get an exception on the List.Add line when trying to run this code:
I am trying to understand the difference between this list: UIRequiredDeviceCapabilities and individual keys
I'm trying to save some UserControl-Infos into a List like this: List<UserControlDetails> myList; public
I'm trying to create a page by using view 2. This page list all
I'm trying to execute this function when a select list's (LevelId0) value change but
I'm trying to do this: int main(void){ u_int64_t NNUM = 2<<19; u_int64_t list[NNUM], i;
I am trying to get Update queries from a list of files using this
I'm trying to illustrate a doubly linked list problem. this is from an old
I was trying to make an array-based linear list, then I compiled this: char

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.