Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6011645
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T02:17:24+00:00 2026-05-23T02:17:24+00:00

I am trying to echo some google analytics javascript code from PHP so it

  • 0

I am trying to echo some google analytics javascript code from PHP so it can be conditionally read based on specific scenarios. I’m having difficulty wrapping my head around the quoting since the code contains /* */ characters. I’m looking for some direction in assigning this type of text to a php variable.

Thanks

$sJS .='<script type="text/javascript">';
$sJS .='/* <![CDATA[ */"';
$sJS .='var google_conversion_language = "en";';
$sJS .='var google_conversion_format = "2";';
$sJS .='var google_conversion_color = "ffffff";';
$sJS .='var google_conversion_value = 0;';
$sJS .='/* ]]> */';
$sJS .='</script>';
$sJS .='<script type="text/javascript" src="http://www.googleadservices.com/page.js">';
$sJS .='</script>';
$sJS .='<noscript>';
$sJS .='<div style="display:inline;">';
$sJS .='<img height="1" width="1" style="border-style:none;" alt="" src="http://www.googleadservices.com/pagead/conversion/997410413/?value=1.00&amp;label=ffr456dj5QIQ7YzN2wM&amp;guid=ON&amp;script=0"/>';
$sJS .='</div>';
$sJS .='</noscript>';
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-23T02:17:24+00:00Added an answer on May 23, 2026 at 2:17 am

    You don’t need to do it line by line like that… PHP supports continuation to the next line. This works just fine:

    $sJS = '<script type="text/javascript">
        /* <![CDATA[ */
        var google_conversion_language = "en";
        var google_conversion_format = "2";
        var google_conversion_color = "ffffff";
        var google_conversion_value = 0;
        /* ]]> */
        </script>
        <script type="text/javascript" src="http://www.googleadservices.com/page.js">
        </script>
        <noscript>
        <div style="display:inline;">
        <img height="1" width="1" style="border-style:none;" alt="" src="http://www.googleadservices.com/pagead/conversion/997410413/?value=1.00&amp;label=ffr456dj5QIQ7YzN2wM&amp;guid=ON&amp;script=0"/>
        </div>
        </noscript>';
    

    Your string is quoted with single quotes, there are no single quotes inside of it, and there are no backslashes or escape sequences.

    Visibly working (if you view source) at: http://gfosco.kodingen.com/phpjs.php

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am trying to echo out some JavaScript, but I can't get the formatting
I am trying to scrap some content from a website but the code below
Im trying to using Google Area Chart and PHP to display some data. problem
im trying to echo mediaplayer embed code with IF statement. is there any way
I have an element like this: <div id=foo_<?php echo $id;?> class=hidden></div> I'm trying if
I am trying to echo some text if my loop returns with no data
Im trying to rezise some images that are imported from a folder. It doesent
I'm trying to add some Google AdSense in a RSS stream. I don't want
I'm trying to write some code to work with an htdigest password file. The
I'm trying to display an array of postcodes onto a google map using PHP

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.