Home/ Questions/Q 8933771
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-06-15T09:37:32+00:00

I am trying to enhance a small C++ project with CUDA. My project is

  • 0

I am trying to enhance a small C++ project with CUDA.
My project is using a custom library’s classes and functions for example Matrix3d, Vector3d, Plane2d etc. They are mostly geometric objects.

When I try to use my code in the device (either __host__ __device__ functions or a kernel) all the library functions/objects are considered as host code and I get multiple warnings and errors for example error: identifier "Plane3d::~Plane3d" is undefined in device code

Is there a way to use my library on device as well? How is it done?
I don’t have experience on CUDA and C++ (I have only used CUDA with simple C code without classes) so I don’t get the strategy very well.

Is there a method to avoid changing the library source code? It is possible to change the library’s code but it would be better if I could avoid it.

Thanks a lot.

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    There is no particular problem with using C++ classes in CUDA. The object model is only slightly different to standard C++.

    Any structure or class data members are automatically defined in whichever memory space (so host or device) the class or structure is instantiated in. What is not automatic is the code generation for function members and operators within classes and structure. The programmer must explicitly define and compile those for whichever memory space the object will be instantiated in. This latter requirement means you must have both __device__ and __host__ definitions of each function you call within the object. This includes the constructor and destructor, the latter being the error you show in your question.

    • 0