Question

I am trying to execute a simple program in PHP with Mysql using IF ELSE Condition

My code is executing IF part but not Else

Please Help me
and here is my code

<?PHP


$userInputEntities = htmlentities($userInput);
echo $userInputEntities;

$username = "admin";
$password = "1234565";
$database = "tele";
$server = "localhost";
$db     = new PDO (
    "mysql:host=$server;dbname=$database", 
    "$username", 
    "$password");
$id     = $_REQUEST['cid'];
if ($db) {
    $SQL = $db->prepare("SELECT * FROM user WHERE uid = :id");
    $SQL -> execute(array(':id'=>$id));
    while ($row = $SQL->fetch(PDO::FETCH_ASSOC)) {
        if ($id=="$row[uid]") {
            echo "Welcome";
        } else {
            echo "Sorry You Have not registered with our service";
        }
    }
}

&
My Database table is ‘user’

  uid           name
   1            Manoj
   2            pranay   only two rows i have in table

If user input availble in table then it should print if part and if user not found then it should print else part
Please Help me, Thankyou

Here If part is printing when IF condition satisfies but not printing else part when If condition fails

Answer 1

The whole while block won’t be executed if your query returns empty set (in case when there’s no user in DB with the given id). So placing else in this block is meaningless: if while body is entered, $id will ALWAYS be equal to $row['uid'] – it’s the condition set in WHERE clause, remember.

You need to check the row count instead, and branch your code based on that, replacing the whole while block with something like this:

$sql = $db->prepare("SELECT * FROM user WHERE uid = :id");
$sql->execute(array(':id'=>$id));
if ($sql->rowCount()) { 
  echo "Welcome";
}
else {
  echo "Sorry, you Have not registered with our service";
}

The alternative is changing the query (SELECT COUNT(*) ...) so it will return the count instead of the whole row, and checking its value against 0.