Question

I am trying to expand a zip file using 7zip but I keep getting the 7zip Usage printout.

The zip exist in c:\temp

The same command succeed in batch window :

C:\TEMP>7z x "tryThis.zip"

I tried adding the workdir path to the file,And also without the working dir,
nothing help. – I can probably run this using CMD/c command but I prefer to keep the code clean

What am I doing wrong?

Thank you!

String  pathTo7ZipExe = "c:\\program files\\7-zip\\7z.exe";
String fileName ="tryThis.zip";
String workingDir = "c:\\temp\\";

Process process = Runtime.getRuntime().exec(
                                     new String[]{pathTo7ZipExe},
                                     new String[]{" x \"" + fileName +"\""},
                                     new File(workingDir)); 

BufferedReader in = new BufferedReader(new InputStreamReader(process.getInputStream()));  
String line;  
while ((line = in.readLine()) != null) {  
      System.out.println(line);  
}  
// wait for zip to end.
int exitVal = process.waitFor();  

Answer 1

Please have a look at the documention for Runtime.exec

What you were actually trying to do is calling 7-zip without arguments and providing the arguments as your environment. Environment is something like Windows PATH etc.

so you would probably want to do something like:

Runtime.getRuntime().exec(new String[]{pathToZipExe, "x", fileName}, null, new File(workingDir));

On the other hand I would strongly advise to have a look on ZipInputStream which is included in java – using that you can also unpack zip files.

Cheers