Question

I am trying to explain the details so that this is easy to understand.

I want a list of month and year based on the difference of month and year.

I am implementing search functionality based on start month with year and end month with year.
So!

start Selection – 01(month)-2009 (Yr)

End selection 10(month)-2009 (Yr)

What I want from MySQL is:

Month                        Year
JAN                          2009
FEB                          2009
MAR                          2009
APR                          2009
MAY                          2009
JUN                          2009
JUL                          2009
AUG                          2009
SEP                          2009
OCT                          2009

Answer 1

FractalizeR answer is the right one.

Just let me expand by defining the functions:

function GetMonthsFromDate($myDate) {
  $year = (int) date('Y',$myDate);
  $months = (int) date('m', $myDate);
  $dateAsMonths = 12*$year + $months;
  return $dateAsMonths;
}

function GetDateFromMonths($months) {
  $years = (int) $months / 12;
  $month = (int) $months % 12;
  $myDate = strtotime("$years/$month/01"); //makes a date like 2009/12/01
  return $myDate;
}

PS: tried to post as a comment but the formating got screwed.
(Of course this functions could be rewritten as one liners but wanted to be more readable)