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Home/ Questions/Q 8870777
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T17:49:20+00:00 2026-06-14T17:49:20+00:00

I am trying to extract a portion from a string in python 2.7 using

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I am trying to extract a portion from a string in python 2.7 using a regular expression (re module).

The best I can get is

res = "{{PakBusPort_somename} 11942 pakbus-port 1}\r\n{{Somename} 5436 CR800-series 2}"
p = re.compile('PakBusPort_')
m = p.findall( res )

Which will give me “PakBusPort_”. But I also need it to give me the “somename” portion.

Basically I need everything in between { and } that starts with “PakBusPort_”. I have tried

p = re.compile('PakBusPort_.*}}')

But no results.

I am a bit of a noob with regular expressions so any help would be appreciated.

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  1. Editorial Team
    Editorial Team
    2026-06-14T17:49:21+00:00Added an answer on June 14, 2026 at 5:49 pm
    In [71]: p = re.compile(r'{PakBusPort_(.*?)}')
    
    In [72]: p.findall(res)
    Out[72]: ['somename']
    

    If you also need to include PakBusPort_, move the opening parenthesis:

    In [73]: p = re.compile(r'{(PakBusPort_.*?)}')
    
    In [74]: p.findall(res)
    Out[74]: ['PakBusPort_somename']
    

    The question mark is needed to make the match non-greedy, meaning that it’ll stop at the first } rather than matching everything till the last one.

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