Question

I am trying to fetch my mysql records into a table, each cell must have one image only.

The problem is that the photo duplicated 5 times according to the number I need to fill each row.

Here is my code:

<table width="%" border="1" bordercolor="#F7F7F7" align="center" cellspacing="10" cellpadding="5">

       <tr>

       <?
       for($i=0;$i<=5;$i++)
       { 

         echo "<td width=125 height=125><img width=125 height=125 src=images/".$info['photo'] ."></td>"; 
         } }?>
       </tr>
     </table>

How can I correct this code to make each photo fetched one time for each cell?

***** EDIT *****

I put the while inside the table, and the fetching is okay now, but it still fetch in the same row, I need to make something to stop fetching until I have 5 cells in the same row, then continue to fetch in a new row.

 <table width="%" border="1" bordercolor="#F7F7F7" align="center" cellspacing="10" cellpadding="5">

       <tr>


       <?

       while($info = mysql_fetch_array( $data  )) 
 {  
 ?>

        <td width=125 height=125 ><img width=125 height=125 src=images/<? echo ($info['photo']); ?>></td>


     <?   } ?>
       </tr>

Answer 1

You’re not changing $info['photo'] inside the loop. That’s why you’re echoing the same photo five times.

Depending how your code looks like you can modify your code like this:

$result = mysql_query($your_query);

while ($row = mysql_fetch_array($result, MYSQL_NUM)) {
    echo("<td width=\"125\" height=\"125\"><img width=\"125\" height=\"125\" src=\" images/". $row["photo"] ."></td>");
}