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Home/ Questions/Q 259821
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T22:17:46+00:00 2026-05-11T22:17:46+00:00

i am trying to find a certain tag in a html-page with java. all

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i am trying to find a certain tag in a html-page with java. all i know is what kind of tag (div, span …) and the id … i dunno how it looks, how many whitespaces are where or what else is in the tag … so i thought about using pattern matching and i have the following code:

 // <tag[any character may be there or not]id="myid"[any character may be there or not]>
 String str1 = "<" + Tag + "[.*]" + "id=\"" + search + "\"[.*]>";
 // <tag[any character may be there or not]id="myid"[any character may be there or not]/>
 String str2 = "<" + Tag + "[.*]" + "id=\"" + search + "\"[.*]/>";
 Pattern p1 = Pattern.compile( str1 );
 Pattern p2 = Pattern.compile( str2 );
 Matcher m1 = p1.matcher( content );
 Matcher m2 = p2.matcher( content );
 int start = -1;
 int stop = -1;
 String Anfangsmarkierung = null;
 int whichMatch = -1;

 while( m1.find() == true || m2.find() == true ){

        if( m1.find() ){
            //System.out.println( " ... " + m1.group() );
            start = m1.start();
            //ende = m1.end();
            stop = content.indexOf( "<", start );
            whichMatch = 1;
        }
        else{
            //System.out.println( " ... " + m2.group() );
            start = m2.start();
            stop = m2.end();
            whichMatch = 2;
        }
 }

but i get an exception with m1(m2).start(), when i enter the actual tag without the [.*] and i dun get anything when i enter the regular expression 🙁 … i really havent found an explanation for this … i havent worked with pattern or match at all yet, so i am a little lost and havent found anything so far. would be awesome if anyone could explain me what i am doing wrong or how i can do it better …

thnx in advance 🙂

… dg

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T22:17:46+00:00Added an answer on May 11, 2026 at 10:17 pm

    Here is an example for what you’re trying to do adapted from one of my notes:

    import java.util.regex.Matcher;
    import java.util.regex.Pattern;
    
    public class Main {
    
        public static void main(String[] args) {
    
            String tag = "thetag";
            String id = "foo";
    
            String content = "<tag1>\n"+
                    "<thetag name=\"Tag Name\" id=\"foo\">Some text</thetag>\n" +
                    "<thetag name=\"AnotherTag\" id=\"foo\">Some more text</thetag>\n" +
                    "</tag1>";
    
            String patternString = "<" + tag + ".*?name=\"(.*?)\".*?id=\"" + id + "\".*?>";
    
            System.out.println("Content:\n" + content);
            System.out.println("Pattern: " + patternString);
    
            Pattern pattern = Pattern.compile(patternString);
    
            Matcher matcher = pattern.matcher(content);
    
            boolean found = false;
            while (matcher.find()) {
                System.out.format("I found the text \"%s\" starting at " +
                        "index %d and ending at index %d.%n",
                        matcher.group(), matcher.start(), matcher.end());
                System.out.println("Name: " + matcher.group(1));
                found = true;
            }
            if (!found) {
                System.out.println("No match found.");
            }
        }
    }
    

    You’ll notice that the pattern string becomes something like <thetag.*?name="(.*?)".*?id="foo".*?> which will search for tags named thetag where the id attribute is set to “foo”.

    Note the following:

    • It uses .*? to weakly match zero or more of anything (if you don’t understand, try removing the ? to see what I mean).
    • It uses a submatch expression between parenthesis (the name="(.*?)" part) to extract the contents of the name attribute (as an example).
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