Question

I am trying to find a good way to return a value in a url page.

I want that everytime “span class=” button” is listed I can grab the next line

"span class=" button" 
0.87

I want to get 0.87

I am trying:

 import urllib

 url = 'http://test.com'
 sock = urllib.urlopen(url)
 content = sock.read().splitlines()
 sock.close()

 for i in content:
     i = i.strip()

This is where I get stuck, how do I get the next line?

Answer 1

If this is HTML you could use an html parser like BeautifulSoup

buttons = soup.findAll('span', {'class': 'button'})
for button in buttons:
  button.nextSibling

this uses nextSibling which looks like it has been changed to next_sibling in the most recent version of beautiful soup?

Python has a built in HTMLParser
if your data is

<span class="button">
0.87
</span>

you could create a class like in the example