Question

I am trying to find a way to use
FILE * fopen ( const char * filename, const char * mode ); but passing the filename indirectly. i would also like to know how to indirectly call a function with name taken straightly from argv[].I dont want to store the string in a buffer char array. For example:

 int main (int argc,char *argv[])
    {
      FILE *src;
      ...
      src = fopen("argv[1]", "r");   //1st:how to insert the name of the argv[1] for example?
      ...
     function_call(argc,argv);    //2nd:and also how to call a function using directly argc argv
     ...
     }
    void create_files(char name_file1[],char name_file2[])
    {...}

Do i have to store length and the string of chars in order to call a function? (regarding the 2nd question) 🙂

Answer 1

You can simply use argv[1], it’s a char *:

if (argc < 2)
    /* Error. */

src = fopen(argv[1], "r");

Same goes for create_files.

create_files(argv[1], argv[2]);