Question

I am trying to find out a way to check whether a file is already opened in COBOL, so that I can open it if it is closed or close it if it is opened.

Thnx.

Answer 1

Check the FILE STATUS and act accordingly.

Try the following:

Add a FILE-STATUS under the FILE-CONTROL, for example:

    FILE-CONTROL.
        SELECT  MYFILE ASSIGN MYDD
                ORGANIZATION SEQUENTIAL
                ACCESS       SEQUENTIAL
                FILE STATUS  MYFILE-STATUS.

Declare a FILE STATUS variable in WORKING-STORAGE
as a PIC X(2) value, for example:

           01 MYFILE-STATUS   PIC X(2).
              88 MYFILE-ALREADY-OPEN   VALUE '41'.

Then in the PROCEDURE DIVISIONissue an OPEN for your
file. Immediately following that, test the value of FILE STATUS
as in:

    OPEN MYFILE....
    IF MYFILE-ALRADY-OPEN
       CLOSE MYFILE...
    END-IF
    IF MYFILE-STATUS <> '00'
       perform some sort of general error routine
    END-IF

Values of FILE STATUS where the first character is not a ‘9’, are
COBOL standard values so testing for ’41’ to detect an already open file
should work on all COBOL implementations. Beware when the first character is a ‘9’,
these are vendor specific file status codes. Check out the following link for
a good introduction to using COBOL FILE STATUS: http://www.simotime.com/vsmfsk01.htm