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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T11:51:34+00:00 2026-05-12T11:51:34+00:00

I am trying to find out if a given executable (or library) is compiled

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I am trying to find out if a given executable (or library) is compiled for 32-bits or 64-bits from Python. I am running Vista 64-bits and would like to determine if a certain application in a directory is compiled for 32-bits or 64-bits.

Is there a simple way to do this using only the standard Python libraries (currently using 2.5.4)?

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  1. Editorial Team
    Editorial Team
    2026-05-12T11:51:34+00:00Added an answer on May 12, 2026 at 11:51 am

    The Windows API for this is GetBinaryType. You can call this from Python using pywin32:

    import win32file
    type=GetBinaryType("myfile.exe")
    if type==win32file.SCS_32BIT_BINARY:
        print "32 bit"
    # And so on
    

    If you want to do this without pywin32, you’ll have to read the PE header yourself. Here’s an example in C#, and here’s a quick port to Python:

    import struct
    
    IMAGE_FILE_MACHINE_I386=332
    IMAGE_FILE_MACHINE_IA64=512
    IMAGE_FILE_MACHINE_AMD64=34404
    
    f=open("c:\windows\explorer.exe", "rb")
    
    s=f.read(2)
    if s!="MZ":
        print "Not an EXE file"
    else:
        f.seek(60)
        s=f.read(4)
        header_offset=struct.unpack("<L", s)[0]
        f.seek(header_offset+4)
        s=f.read(2)
        machine=struct.unpack("<H", s)[0]
    
        if machine==IMAGE_FILE_MACHINE_I386:
            print "IA-32 (32-bit x86)"
        elif machine==IMAGE_FILE_MACHINE_IA64:
            print "IA-64 (Itanium)"
        elif machine==IMAGE_FILE_MACHINE_AMD64:
            print "AMD64 (64-bit x86)"
        else:
            print "Unknown architecture"
    
    f.close()
    
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