Question

I am trying to find the attribute value of the title attribute.

Now, I have a list of similar links on the same page and I want to select the first link and get its title attribute.

I have used the following selenium command:

self.se.get_attribute("css=a[href*='radio?rid=']:nth-of-type(1)@title")

But it is giving me an error.

Could someone please help me figure out the problem?
Thanks

Answer 1

You should use XPath syntax instead of CSS selectors. You didn’t post any HTML to match, so therefore a made up example: to get the title of the first link found in a div with id myDiv, use the following:

self.se.get_attribute("xpath=//div[@id='myDiv']//a[1]@title")

Where:

• //div[@id='myDiv'] matches any div with id “myDiv”;
• //a[1] select the first link found anywhere in the previously selected div (use 2 for the second, and so on.
• @title specifies the attribute you want to retrieve.