Question

I am trying to find the size of a file using the -s operator. It looks like this:

my $filesz = -s $filename

I tried lots of various way, but it can not get this size.
However, if I give static content instead of filename, it works fine

For example:

$filesz = -s "/tmp/abc.txt"

This works fine.

I tried adding " in the filename, it didn’t work. I removed \n from filename using chomp, but the problem remains the same. What’s wrong here?

Answer 1

-s $filename works just fine; the only conclusion is that there’s no file with the name contained in $filename. Take a very close look at the contents of $filename, and make sure that your working directory is what you think it is.