Home/ Questions/Q 6389723
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-25T03:26:22+00:00

I am trying to fix a problem for hours and I just gave up

  • 0

I am trying to fix a problem for hours and I just gave up trying to search & code & see if it works.

Maybe it will be better to explain with simple code what I am trying to do;

<script>
test1       = $('input:text[name=test1]');
test2       = $('input:text[name=test2]');
test3       = $('input:text[name=test3]');

var obj = [];
obj.push(test1);
obj.push(test2);
obj.push(test3);

$.each(obj, function(key, value) {
    console.log ('value : ' + value.val());
});

</script>
</head>

<body>
<input name="test1" type="text" value="1"/>

<input name="test2" type="text" value="2"/>

<input name="test3" type="text" value="3"/>
</body>
</html>

What I am trying to do is;

  1. Define variables which will be assign to DOM element.
  2. Create an array and put those variables which are assigned to DOM elements.
  3. Loop them and get their values etc…

Is there a way to do that? I am really tired after trying to make it work for hours.

Thank you for your help and time in advance.

EDIT:

Of course the code above wasn’t something I was trying to achieve. I have a form which has over 700 lines of Jquery code and I had a problem in one of my functions.

The principle was the same so I decided to make something really short and clearly understandable.
$value was just bad copy & paste. Before I realized I didn’t delete all of my old code (just $ was left) and edited my post, some people already replied. It wasn’t the correct answer but I just didn’t want to close the question without giving points to anyone.

The code above will not work unless if you change it to;

$(document).ready(function(){
 // Put the code here
});

Considering my jquery code is in between <head> </head> I have to use $(document).ready

I hope this will help someone.

I am not newbie in Jquery, I don’t know why and how I could make such mistake.

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Try doing this: 

    $.each(obj, function() {
    console.log ('value : ' + this.val());
});

    Demo

    • 0