Question

I am trying to generate a table that takes data from a mysql database. There are 8 columns but the number of rows is variable depending on the amount of info from the database. The problem I’m running into is that I have two things that are variable and I don’t know how to use two while loops (or if that’s the right choice).

The code below can generate a table with 8 columns and a variable amount of rows but I don’t know how to replace thing with sequential integers. I would like each cell to have just one integer in it sequentially like a while loop until the numbers = $end.

CODE:

<?php

$end=82;  //will get all this data from a dabase
$rows=ceil($end/8);
$x=0;
$start=0;
?>
<table>
<?php
While ($x<=$rows){


echo"

        <tr>
        <td>
            thing
        </td>
        <td>
            thing
        </td>
        <td>
            thing
        </td>
        <td>
            thing
        </td>
        <td>
            thing
        </td>
        <td>
            thing
        </td>
        <td>
            thing
        </td>
        <td>
            thing
        </td>
    </tr>

    ";
    $x++;
    }
?>
</table>

Answer 1

This will output eight numbers per row starting at 1 and going to $end. I am unsure of what $maxprobs is here.

<?php

$end=82;  //will get all this data from a dabase
$rows=ceil($end/8);
$x=0;
$start=0;
?>
<table>
<?php
while($x<=$rows) {
  echo "<tr>";
  for ($y = 0; $y < 8; $y++, $start++) {
    if ($start <= $end) echo "<td>$start</td>";
  }
  echo "</tr>";
  $x++;
}
?>
</table>