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Home/ Questions/Q 6004427
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T01:15:43+00:00 2026-05-23T01:15:43+00:00

i am trying to get a list of names from MySQL table useing php

  • 0

i am trying to get a list of names from MySQL table useing php and jQuery autocomplete function but i get no result.could you help plz

here is jQuery

<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.2/jquery.min.js" 
  type="text/javascript"></script> 

<script language="javascript" type="text/javascript">
  function findmatch(str){
    if (str.length>0){
      $('#found').load('SelectQury.php?n='+str);
    }
  }//fun
</script>
</head>

<body>
  <div id="container">
    <input type="text" name="text" id="textfield" autocomplete="off"    
     onkeyup="findmatch(this.value);"/>
    <div id="found" >non found</div>
  </div>

</body>
</html>

php code

if(isset($_POST['text'])){
    $s=$_POST['text'];

$query="SELECT FROM student WHERE name LIKE '$s%'";
$result=mysql_query($query) or die ('Wrong query : ' . mysql_error() );
$string='';
while($row = mysql_fetch_assoc($result)){
     $string.= $row['name'];
}
echo $string;
}else{
  echo 'wrong GET keywoord';

}//ifisset
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T01:15:44+00:00Added an answer on May 23, 2026 at 1:15 am

    Two problems:

    1. you are sending the value as "GET" method `?n=` and accessing in the PHP code as `$_POST`
    2. the passed variable is `n` and not `text`
    3. error in mysql query
    

    Use the following PHP code:

    if(isset($_GETT['n'])){
       $s=$_GET['n'];
    
        $query="SELECT * FROM student WHERE name LIKE '$s%'";
        $result=mysql_query($query) or die ('Wrong query : ' . mysql_error() );
        $string='';
        while($row = mysql_fetch_assoc($result)){
             $string.= $row['name'];
        }
          echo $string;
      }else{
         echo 'wrong GET keywoord';
    
    }
    
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