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Home/ Questions/Q 3952404
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T01:50:48+00:00 2026-05-20T01:50:48+00:00

I am trying to get a random number generator that will be biased in

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I am trying to get a random number generator that will be biased in that it takes a number, and prints a number that is likely to be close. Here’s what I have now:

def biasedRandom(rangen, rangex, target, biaslevel=1):
    if rangen > rangex:
        raise ValueError("Min value is less than max value.")
        return
    if not target in range(rangen, rangex):
        raise ValueError("Bias target not inside range of random.")
        return

    num = random.randint(rangen, rangex)
    for i in range(biaslevel):
        distance = abs(num - target)
        num -= random.randint(0, distance)

    return num

This works pretty well, however it has on occasion given completely outrageous numbers; e.g. it once gave -246174068358 for (1,100,30,60). I figure there is just a bug in there that I am not seeing.

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-20T01:50:48+00:00Added an answer on May 20, 2026 at 1:50 am

    raise exits the function – you do not need to follow raise with return

    target in range(lo, hi) is inefficient; why not lo <= target < hi?

    Edit:

    import random
    def biasedRandom(lo, hi, target, steps=1):
        if lo >= hi:
            raise ValueError("lo should be less than hi")
        elif target < lo or target >= hi:
            raise ValueError("target not in range(lo, hi)")
        else:
            num = random.randint(lo, hi)
            for i in range(steps):
                num += int(random.random() * (target - num))
            return num
    

    As steps is increased, this will pretty rapidly converge on target; you might want to do some trial distributions to make sure that you are getting what you expected, or try using random.gauss instead.

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