Question

I am trying to get an age in years and months from a given DOB. Right now, my code looks like this:

COLUMN name FORMAT A25
SELECT sNo, fName||CHR(13)||lName Name, sex, TRUNC((CURRENT_DATE - dob) / 365.24, 1) Age
FROM Staff
WHERE position IN ('Manager', 'Secretary')
ORDER BY age DESC;

And it gives me Age outputs in decimal numbers (such as 58.6) which I understand, but I am needing to convert that .6 into a month somehow.

I am thinking that my method of doing this conversion isn’t the most efficient, but I have been searching for hours for a solution, but to no avail. I’ve seen DATEDIFF, but I keep getting an invalid identifier error when trying to use it.

Any ideas?

Answer 1

How about something like this:

SELECT sNo, fName||CHR(13)||lName Name, sex, 
  TRUNC((CURRENT_DATE - dob) / 365.24, 1) Age,
  TRUNC(MONTHS_BETWEEN(CURRENT_DATE, dob) / 12) YEARS,
  MOD(TRUNC(MONTHS_BETWEEN(CURRENT_DATE, dob)), 12) MONTHS
FROM Staff
WHERE position IN ('Manager', 'Secretary')
ORDER BY age DESC;

And here is the SQL Fiddle.

And this should get you the days as well: http://sqlfiddle.com/#!4/f3a57/4

SELECT sNo, fName||CHR(13)||lName Name, sex, 
  TRUNC((CURRENT_DATE - dob) / 365.24, 1) Age,
  TRUNC (MONTHS_BETWEEN (CURRENT_DATE, dob) / 12) YEARS,
  MOD (TRUNC (MONTHS_BETWEEN (CURRENT_DATE, dob)), 12) MONTHS,
  TO_DATE (CURRENT_DATE) - 
      ADD_MONTHS (dob,TRUNC (MONTHS_BETWEEN (CURRENT_DATE, dob))) DAYS
FROM Staff
WHERE position IN ('Manager', 'Secretary')
ORDER BY age DESC;

Good luck.