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Home/ Questions/Q 6140431
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T18:07:03+00:00 2026-05-23T18:07:03+00:00

I am trying to get data from a database. I have the following code

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I am trying to get data from a database. I have the following code for that:

mysql_select_db($database_tony, $tony);
$query_rsTony = "SELECT `tony feature`.`text` 
                   FROM `tony feature`";

$rsTony = mysql_query($query_rsTony, $tony)) ;
if ($rsTony) echo 'set';
else echo 'not set'; 
$row_rsTony = mysql_fetch_row($rsTony)); 
if ($row_rsTony) echo 'set';
else echo 'not set';
$totalRows_rsTony = mysql_num_rows($rsTony);
$text = $row_rsTony['text'];

I am getting the output:

set not set

EDIT
I added the changes said below and I have the above output.
I don’t know why the mysql_fetch_row($rsTony) is not working — any ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T18:07:03+00:00Added an answer on May 23, 2026 at 6:07 pm

    You need to use result which returned by mysql_query as mysql_fetch_row parameter:

    $rsTony = mysql_query($query_rsTony, $tony)) ;
    if ($rsTony) echo 'set';
    else echo 'not set';
    

    UPDATE

    $row_rsTony = mysql_fetch_row($rsTony)); 
    if ($row_rsTony) echo 'set';
    else echo 'not set';
    //....
    

    So, you final code should look like

    $rsTony = mysql_query($query_rsTony, $tony)) ;
    if ($rsTony) echo 'set';
    else echo 'not set';
    $row_rsTony = mysql_fetch_row($rsTony)); 
    if ($row_rsTony) echo 'set';
    else echo 'not set';
    
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