Question

I am trying to get every instance of a domain where there user is equal to current logged in user.
My code at the minute is:

def list(Integer max) {
    params.max = Math.min(max ?: 10, 100)
    if (lookupPerson().username == "admin"){
         adminList(max)
    }
    else{

        def childList = []
        def i = 1
     Child.list().each(){
         if(Child.get(i).user.username == lookupPerson().username){
             def child = Child.get(i)
             childList.add(child)
         }
          i++
     }
        [childInstanceList: childList.list(params), childInstanceTotal: childList.count()]
    }


}

This gives me the following error
No signature of method: java.util.ArrayList.list() is applicable for argument types: (org.codehaus.groovy.grails.web.servlet.mvc.GrailsParameterMap) values: [[action:list, controller:child, max:10]] Possible solutions: last(), first(), asList(), toList(), is(java.lang.Object), wait()

I’m sure there must be an easier and better way of doing this.
any ideas?

Answer 1

You can probably do what you’re after with a criteria query:

def childList = Child.createCriteria().list(params) {
  user {
    eq('username', lookupPerson().username)
  }
}

If your params has pagination parameters then the “total” will be available as childList.totalCount, you don’t need to calculate it separately.