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Home/ Questions/Q 7966547
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T06:27:37+00:00 2026-06-04T06:27:37+00:00

I am trying to get loaded one self-relation property eagerly using contains_eager option to

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I am trying to get loaded one self-relation property eagerly using contains_eager option to avoid two joins when ordering or searching using one of relation columns. My model objects looks as:

class Usuario(DeclarativeBase):
    __tablename__ = 'usuarios'
    __table_args__ = {'mysql_engine':'InnoDB'}

    id=Column(Integer, primary_key=True)
    usuario=Column(Text) 
    ...
    resellers_id=Column(Integer, ForeignKey('usuarios.id')) 
    ....
    reseller = relation('Usuario', remote_side = [id])

I am using to get the data:

u= DBSession.query(Usuario).options(contains_eager('reseller'))\
            .outerjoin(self.usuarios_padre, Usuario.resellers_id == self.usuarios_padre.id)\
            .filter(Usuario.id=1)\
            .order_by(self.usuarios_padre.usuario).one()

where self.usuarios_padre is one alias of Usuario

If I access u.reseller.usuario I get the same as u.usuario instead getting usuario from parent

Any idea where the problem is? I tryied to define the relation using lazy=”joined” without result.

Regards

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  1. Editorial Team
    Editorial Team
    2026-06-04T06:27:39+00:00Added an answer on June 4, 2026 at 6:27 am

    The issue is that you load two sets of Usuario objects in one query, and in order to solve the problem, you need to use the aliased and then explicitely specify the aliased parent in both the join and the contains_eager:

    qry = session.query(Usuario).filter(Usuario.id==1)
    
    # join using the aliased. Use *outerjoin* in order to still get the result for those without a parent
    res = aliased(Usuario)
    qry = qry.outerjoin((res, Usuario.reseller))
    
    # specify which table/alias represents the *contained* relationship
    qry = qry.options(contains_eager(Usuario.reseller, alias=res))
    
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