Question

I am trying to get the default image if no image is uploaded by the user but I get always the image which is uploaded by the user and the default does not show up.

Here is SQL query code and CSS part.

$query="INSERT INTO tbl_images (f_naam) VALUES ('$filename')";
if($result=mysql_query($query) or die ('query fout') ){
?>
<img src="data/<?php echo $filename; ?>"  width="220" />
<?php }else{ ?>
        <img src="http://www.istockphoto.com/file_thumbview_approve/12716227/2/istockphoto_12716227-close-up-of-a-cute-young-couple-smiling-togetherjpg" width="220" />
        </div>
<?php } ?>

Answer 1

i am not sure if this is the problem BUT i suspect that even if $filename is empty, the query would run successfully and you would go into the section trying to display the uploaded image. So you might want to put a check on $filename and make sure it has something before running the query.

I might do it something like this, untested code though.

<?php 

    $picture_to_show = "http://www.istockphoto.com/file_thumbview_approve/12716227/2/istockphoto_12716227-close-up-of-a-cute-young-couple-smiling-togetherjpg";

    if($filename){
        $query="INSERT INTO tbl_images (f_naam) VALUES ('$filename')";
        if($result=mysql_query($query) ){
            $picture_to_show = "data/".$filename;
        }
    }   

?>
<img src="<?php echo $picture_to_show; ?>"  width="220" />