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Home/ Questions/Q 6753345
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:09:01+00:00 2026-05-26T13:09:01+00:00

I am trying to get the image type in the database but the below

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I am trying to get the image type in the database but the below isn’t working. How do I detect if the image is png, jpeg or gif?

if(isset($_POST['submit'])) {
    $fileType = $_FILES['image']['type'];
    $tmpname = $_FILES['image']['tmp_name'];
    $fp = fopen($tmpname,'r');
    $data = fread($fp,filesize($tmpname));
    $data = addslashes($data);
    fclose($fp);

    $update = mysql_query("UPDATE avatar SET image1='$data',type='$fileType' WHERE username='$user'",$this->connect);
} else {
    echo "<form enctype='multipart/form-data' action='http://www.example.com/cp/avatar' method='post'>
        <div id='afield1' >Upload</div><div id='afield2'><input type='hidden' name='MAX_FILE_SIZE' value='102400' /><input type='file' size='25' name='image' /></div>
        <div id='asubmit'><input type='submit' name='submit' class='button' value='Save Changes' /></div>
        </form>";
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:09:02+00:00Added an answer on May 26, 2026 at 1:09 pm

    use getimagesize() or exif_imagetype()

    // integer - for example: IMAGETYPE_GIF, IMAGETYPE_JPEG etc.
    $type   = exif_imagetype($_FILES['image']['tmp_name']);
    

    and

    $info   = getimagesize($_FILES['image']['tmp_name']);
    $mime   = $info['mime']; // mime-type as string for ex. "image/jpeg" etc.
    $width  = $info[0];      // width as integer for ex. 512
    $height = $info[1];      // height as integer for ex. 384
    $type   = $info[2];      // same as exif_imagetype
    

    Mind that exif_imagetype is much faster than getimagesize. Check documentation for more info.

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