Question

I am trying to get the path of my python script.

I know ‘sys.argv[0] gives me the path and the name of my python script.

how can I just get the path?

I tried:

 print sys.argv[0]
    path = sys.argv[0].split("/")
    scriptpath = "".join(path[0:-1])

But it does not add back the path separator.

Answer 1

Prefer to use __file__, like this:

os.path.dirname(os.path.realpath(__file__))

Note: using sys.argv[0] may not work if you call the script via another script from another directory.